What is the tire pressure at -20°F compared to 90°F, assuming the starting pressure was 32 psi?
C=(F-32) X (5/9)
K= 273+ C
T1=90°F=32.2°C=305.2K
T2=-20°F=-12.77°C=260.2K
P1=32Psi
P2=X
P1/T1=P2/T2
32Psi/305.2K=X/260.2K
=32PsiX260.2K/305.2K= 27.28 psi
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